9-1/t-8/t^2=0

Solution for 9-1/t-8/t^2=0 equation:

D( t )

t^2 = 0

t = 0

t^2 = 0

t^2 = 0

1*t^2 = 0 // : 1

t^2 = 0

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

9-(1/t)-(8/(t^2)) = 0

9-t^-1-8*t^-2 = 0

t_1 = t^-1

9-8*t_1^2-1*t_1^1 = 0

9-8*t_1^2-t_1 = 0

DELTA = (-1)^2-(-8*4*9)

DELTA = 289

DELTA > 0

t_1 = (289^(1/2)+1)/(-8*2) or t_1 = (1-289^(1/2))/(-8*2)

t_1 = -9/8 or t_1 = 1

t_1 = -9/8

t^-1+9/8 = 0

1*t^-1 = -9/8 // : 1

t^-1 = -9/8

-1 < 0

1/(t^1) = -9/8 // * t^1

1 = -9/8*t^1 // : -9/8

-8/9 = t^1

t = -8/9

t_1 = 1

t^-1-1 = 0

1*t^-1 = 1 // : 1

t^-1 = 1

-1 < 0

1/(t^1) = 1 // * t^1

1 = 1*t^1 // : 1

1 = t^1

t = 1

t in { -8/9, 1 }